PHP-Ajax RSS提要示例

的RSS

真正简单的联合组织用于发布网站上经常更新的信息，例如音频，视频，图像等。我们可以使用Ajax和php将RSS feed集成到网站。此代码演示了如何在我们的网站中显示RSS feed。

Index.html

索引页应如下-

<script>
         function showRSS(str) {
            if (str.length == 0) { 
               document.getElementById("output").innerHTML = "";
               return;
            }
         
            if (window.XMLHttpRequest) {
               xmlhttp = new XMLHttpRequest();
            }else {
               xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
            }
            xmlhttp.onreadystatechange = function() {
               if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
                  document.getElementById("output").innerHTML = xmlhttp.responseText;
               }
            }
            
            xmlhttp.open("GET","rss.php?q="+str,true);
            xmlhttp.send();
         }
      </script>
      
   
   
   
      <p>Please Select an option to get RSS:</p>
      
      <form>
         <select onchange="showRSS(this.value)">
            <option value="">Select an RSS-feed:</option>
            <option value="cnn">CNN</option>
            <option value="bbc">BBC News</option>
            <option value="pc">PC World</option>
         </select>
      </form>
      <br>
      
      <div id="output">RSS-feeds</div>
      
   

rss.php

rss.php包含有关如何访问rss提要并将rss提要返回到网页的语法。

<?php $q = $_GET["q"];
   
   if($q == "cnn") {
      $xml = ("http://rss.cnn.com/rss/cnn_topstories.rss");
   }elseif($q == "bbc") {
      $xml = ("http://newsrss.bbc.co.uk/rss/newsonline_world_edition/americas/rss.xml");
   }elseif($q = "pcw"){
      $xml = ("http://www.pcworld.com/index.rss");
   }
    
   $xmlDoc = new DOMDocument();
   $xmlDoc-?>load($xml);
   
   $channel = $xmlDoc->getElementsByTagName('channel')->item(0);
   
   $channel_title = $channel->getElementsByTagName('title')
   ->item(0)->childNodes->item(0)->nodeValue;
   
   $channel_link = $channel->getElementsByTagName('link')
   ->item(0)->childNodes->item(0)->nodeValue;
   
   $channel_desc = $channel->getElementsByTagName('description')
   ->item(0)->childNodes->item(0)->nodeValue;
   
   echo("<p><a href="%22%20.%20%24channel_link%20.%20%22">" . 
      $channel_title . "</a>");
   echo("<br>");
   echo($channel_desc . "</p>");
   
   $x = $xmlDoc->getElementsByTagName('item');
   
   for ($i = 0; $i<=2; $i++) {
      $item_title = $x->item($i)->getElementsByTagName('title')
      ->item(0)->childNodes->item(0)->nodeValue;
      
      $item_link = $x->item($i)->getElementsByTagName('link')
      ->item(0)->childNodes->item(0)->nodeValue;
      
      $item_desc = $x->item($i)->getElementsByTagName('description')
      ->item(0)->childNodes->item(0)->nodeValue;
      
      echo ("<p><a href="%22%20.%20%24item_link%20.%20%22">" .
         $item_title . "</a>");
      echo ("<br>");
      echo ($item_desc . "</p>");
   }
?>

它将产生以下结果-